Hardy Weinberg Equation
Step 1: Find any given information
q2 = .23 Population: 1000
Step 2: Take the square root of .23 to find q. One you found q, subtract it from 1 to find p.
√ q2 = √.23
q = .47
.47 - 1 = .53 therefore, p = .53
Step 3: Get p2 by squaring p. After getting your p and q values you plug them in into 2pq to get that value.
p = .53 p^2 = .53^2 = .28
2pq = 2(.47)(.53) = .49
Step 4: Make sure your calculations are correct ! Use the following equation to check.
p^2 + 2pq + q^2 = 1
.28 + .49 + .23 = 1
Homozygous dominant individual: p^2 : .28
Homozygous recessive individual : q^2 : .23
Frequency of dominant allele: p : .53
Frequency of recessive allele:q : .47
Heterozygous individual : 2pq: .49
Step 5: Multiple p^2, q^2, and 2pq by the population individuals to find geneotypes
p^2 = .28 x 1000 = 280
q^2 = .23 x 1000 = 230
2pq = .49 x 1000 = 490
Frequency of Dominant Alleles: p = .53 = 53%
Frequency of Recessive Alleles: q = .47 = 47%
